VanDyke Software Forums - scripting hanging at if waitforstring statement

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scripting hanging at if waitforstring statement

I was wondering if you guys have a suggestion for a better way of cycling through password.

My current script always hang at the if statement.

Here is my code:

Code:

prompt = "A:"

currentTab = crt.GetScriptTab()

password = ["wrongPass", "rightPass"]





def main():                

        x = 0

        currentTab.Screen.Synchronous = True                

        currentTab.Screen.Send("kernel\r")

        while currentTab.Screen.WaitForString("assword:") == True:

                currentTab.Screen.Send(password[x]+"\r")

                if currentTab.Screen.WaitForString(prompt) == True:                        

                        x = x + 1                

                        currentTab.Screen.Send("kernel\r")        

                else:

                        break



        currentTab.Screen.Send("finished")

        

main()

Here is my output:

Quote:

*A:# kernel
Password:
MINOR: CLI Unidentified command.
*A:# kernel
Password:
Type "exit" to return to CLI.
1->

As you can see the right password was enter on the second try. However, the script will hang at the waitforstring(prompt) line of code and never send the "finished" string. It is waiting for "A:" but we already log into the kernel and it doesn't go to the else statement to break out of the while loop.

WaitForString(), WaitForStrings(), and ReadString() only operate on data that has not yet been displayed to the Screen.

So, if something has already been displayed to the Screen, it's too late to try and branch on something else that you would then try and Wait for.

If you expect to branch script code on a number of different strings that could appear on the Screen, then you must use WaitForStrings(string1, string2, string3, ...) and then branch on the value of the Screen.MatchIndex property (which tells you the left-to-right index -- or top-to-bottom index, depending on how you've structured your code -- of the string that WaitForStrings() found.

This technique is demonstrated in the Jump Host - Handle Secondary Host Connection Attempts example script found in the script examples 'sticky'.

--Jake